There are 15C3 = 15*14*13/(3*2*1) = 455 combinations, and I am NOT even going to try listing them.
5
From 1 to 20, you can pull out 15,504 different groups of 5 numbers, and each group can be lined up in 120 different orders.
None. If you sellect three numbers each time, you can only get combinations of 3, 6, 9, ect but never 4. Also, there seems to be some confusion between people and numbers!
If the order of the 4 numbers matters, then there are (6 x 5 x 4 x 3) = 360 .If the order of the 4 numbers doesn't matter, then there are 15 different groups of 4.
There are different numbers of combinations for groups of different sizes out of 9: 1 combination of 9 digits 9 combinations of 1 digit and of 8 digits 36 combinations of 2 digits and of 7 digits 84 combinations of 3 digits and of 6 digits 126 combinations of 4 digits and of 5 digits 255 combinations in all.
I doubt it. You can get 7,676,760 different groups of 6 numbers out of a bucket of 40 numbers. No website is going to give you that much output for a single input.
Assuming that the question is about4 groups of 4 numbers, andthe order of the groups does not matter.there are 2,627,625 combinations.The number is only 24 times as large is the order of the groups does, in fact matter. However, if the 4 groups can be of any size (provided their total is 16), the question goes beyond my ability - particularly at this time of the day!
To calculate the number of different combinations of 5 numbers chosen from 1 to 25 without repetition, we can use the formula for combinations: nCr = n! / r!(n-r)!. In this case, n = 25 (total numbers) and r = 5 (numbers chosen). Therefore, the number of combinations is 25! / (5!(25-5)!) = 53,130 different combinations.
diagonal
Assuming you are using combinations in the colloquial way (which is the mathematical "permutations" where order of selection does matter) to create a 3 digit number that does not start with 0, ie creating a number that is between 100 and 999 inclusive then: If repeats are not allowed there are 3 × 3 × 2 = 18 possible numbers If repeats are allowed, then there are 3 × 4 × 4 = 48 possible numbers. If you are using combinations in the mathematical sense where order of selection does not matter and are creating groups of 3 digits, then: If repeats are not allowed there are 4 possible groups If repeats are allowed there are 20 possible groups.
This was the Russian chemist Dmitri Mendeleev.
If not using the same number twice: 36x35x34x33x32= 45,239,040 If allowed to use all numbers up to 5 times: 36x36x36x36x36=60,466,176