From 1 to 20, you can pull out 15,504 different groups of 5 numbers,
and each group can be lined up in 120 different orders.
There are only five combinations: 1234, 1235, 1245, 1345 and 2345.
There are twelve possible solutions using the rule you stated.
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
There are 840 4-digit combinations without repeating any digit in the combinations.
The number of combinations, denoted by 11C6 is 11!/[6!*(11-6)!] = 11*10*9*8*7/(5*4*3*2*1) = 462
There are 10C3 = 10*9*8/(3*2*1) = 120 combinations.
pls i need the formular of national game lotto
Including the leading zero, then the answer is 210. Or, allowing for repeating numbers, 10000.
With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753
First digit can be one of four, second can be one of the remaining three etc so 4 x 3 x 2 x 1 = 24 combinations. This is known as factorial 4 (or 4 factorial) and is symbolised as "4!".
You can get only four combinations: They are: 11, 118, 119 and 1189. In a combination, the order of the digits does not matter.
Since a number can have infinitely many digits, there are infinitely many possible combinations.