0
What else can I help you with?
Is this equation linear or nonlinear y2x?
If you mean y = 2x then it is a straight line equation
Is y2x plus 5 linear equation?
If you mean: y = 2x+5 then it is a straight line equation.
How do you graph y2x-2?
If you mean y = 2x-2 then it is a straight line equation whereas the slope is 2 and the y intercept is -2 and its coordinates would be plotted on the Cartesian plane.
What are the lines for the equation y2x-4?
6
Is y2x 5 a linear function?
If you mean: y = 2x+5 then yes it is a linear function of straight line
How is the equation y2x similar to the equation y2x plus 3 How are they different?
The equations ( y = 2x ) and ( y = 2x + 3 ) are similar in that they both represent linear functions with the same slope of 2, indicating that for every unit increase in ( x ), ( y ) increases by 2 units. They differ in their y-intercepts: the first equation has a y-intercept of 0, while the second has a y-intercept of 3, meaning the graph of the second equation is shifted upward by 3 units compared to the first.
What does y2x-4 equal?
If you mean: y = 2x-4 then it is equal to a straight line equation
Can you help me with this simultaneous equation 2x y4 y2x²-x 3?
No because it's not a simultaneous equation but some kind of algebraic expression
What is the solution of the system for yx 6 y2x?
Without a second independent equation, it's not a 'system' yet.
Which choice would be the equation of a parallel to the line represented by this equation y2x-3?
If you mean y = 2x-3 then the parallel equation will have the same slope of 2 but with a different y intercept
What is the equation to a line if it is parallel to Y2X -4 and goes through (15)?
If you mean: y = 2x-4 and (1, 5) then the parallel equation is y = 2x+3
What is the xintercept of y2x 5?
As written this is not a graphable thing. I does not represent a graphable equation because there is no "=" sign. Whatever the equation might be, the x intercept is found by setting y=0, which leaves you with an equation for x, which is the intercept.
