Without a second independent equation, it's not a 'system' yet.
Without a second independent equation, it's not a 'system' yet.
If you mean: y = x^2+4x+3 and y = 2x+6 Then the solution is: x = 1 or x = -3
x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)
It is (6, -1).
If you mean (1) y + 3x = 22 and (2) y + 2x = 16, then (1) y = 22 - 3x (sub this into (2)) (2) (22 - 3x) + 2x = 16 -x = -6 x = 6 y = 22 - 3x = 22 -3(6) = 4 solution: (6,4)
Without a second independent equation, it's not a 'system' yet.
What is the solution set for the equations x-y=2 and -x+y=2
To determine if Yx 6(06) is a solution, I would need more context about the problem or equation it's meant to solve. Without additional information regarding the mathematical scenario or conditions, it's impossible to assess whether Yx 6(06) qualifies as a solution. Please provide more details for a precise answer.
If you mean: y = x^2+4x+3 and y = 2x+6 Then the solution is: x = 1 or x = -3
x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)
It is (6, -1).
6
If you mean (1) y + 3x = 22 and (2) y + 2x = 16, then (1) y = 22 - 3x (sub this into (2)) (2) (22 - 3x) + 2x = 16 -x = -6 x = 6 y = 22 - 3x = 22 -3(6) = 4 solution: (6,4)
(3, 6)-------------------Let's see.(6) = 3(3) - 33(3) - (6) = 36 = 9 - 39 - 6 = 36 = 63 = 3========== (3, 6) is a solution to the system of equations. The only solution? I do not know.
It would be y = 6x.
To find the ordered pair for the expression ( y - x - 5 = yx + 1 ), we need to rearrange the equation. This can be rewritten as ( y - yx = x + 6 ) or ( y(1 - x) = x + 6 ). Solving for ( y ) gives ( y = \frac{x + 6}{1 - x} ). The ordered pair would depend on specific values of ( x ) and ( y ) that satisfy this equation. For example, if ( x = 0 ), then ( y = 6 ), yielding the ordered pair (0, 6).
The expression ( yx^6 ) represents a mathematical term where ( y ) is multiplied by ( x ) raised to the sixth power. This means that ( x ) is multiplied by itself six times, and then the result is multiplied by ( y ). If specific values for ( y ) and ( x ) are provided, the expression can be evaluated further.