Without a second independent equation, it's not a 'system' yet.
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Without a second independent equation, it's not a 'system' yet.
If you mean: y = x^2+4x+3 and y = 2x+6 Then the solution is: x = 1 or x = -3
x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)
It is (6, -1).
If you mean (1) y + 3x = 22 and (2) y + 2x = 16, then (1) y = 22 - 3x (sub this into (2)) (2) (22 - 3x) + 2x = 16 -x = -6 x = 6 y = 22 - 3x = 22 -3(6) = 4 solution: (6,4)