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What are the coordinates of the center of the hyperbola graphed by the equation below?
Wiki User
∙ 11y ago
answer for (x+5)^2/11^2-(y+16)^2/6^2=1
answer for that Question is (-5,-16)
Wiki User
∙ 11y ago
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The ellipse graphed below has its center at -2 2 its horizontal axis is of length 6 and its vertical axis is of length 10 What is its equation?
23
The transverse axis connects what?
The transverse axis is a connection on a hyperbola. It connects the focus, or center, of the hyperbola, and can connect two together.
What is an eccentric circle?
For Ellipse: The 2 circles made using the the ellipse center as their center, and major and minor axis of the ellipse as the dia.For Hyperbola: 2 Circles with centers at the center of symmetry of the hyperbola and dia as the transverse and conjugate axes of the hyperbolaRead more: eccentric-circles
What is the equation for a hyperbola with transverse axis of length 24 and centered at the origin?
The standard form of the equation of a hyperbola with center at the origin isx2/a2 - y2/b2 = 1 where the transverse axis lies on the x-axis,ory2/a2 - x2/b2 = 1 where the transverse axis lies on the y-axis.The vertices are a units from the center and the foci are c units from the center.For both equations, b2 = c2 - a2. Equivalently, c2 = a2 + b2.Since we know the length of the transverse axis (the distance between the vertices), we can find the value of a (because the center, the origin, lies midway between the vertices and foci).Suppose that the transverse axis of our hyperbola lies on the x-axis.Then, |a| = 24/2 = 12So the equation becomes x2/144 - y2/b2 = 1.To find b we need to know what c is.
The ellipse graphed below has its center at -14-10 its horizontal axis is of length 12 and its vertical axis is of length 16 What is its equation?
(x+14)2 + (y+10)2 = 1 62 82
What are the coordinates of the center of the ellipse graphed by the equation below?
Answers provided by: apexvs.com (x+26)2 + (y-11)2 = 1 _____ _____ 732 7 (-26, 11) or 4
What is the term of two lines crossing the center of a graph if its a hyperbola?
The axes of the hyperbola.
The ellipse graphed below has its center at -2 2 its horizontal axis is of length 6 and its vertical axis is of length 10 What is its equation?
23
What are the followings-hyberbola-asymptotes of hyperbola-centre of hyperbola-conjugated diameter of hyperbola-diameter of hyperbola-directrices of hyperbola-eccentricity of hyperbola?
Asymptotes are the guidelines that a hyperbola follows. They form an X and the hyperbola always gets closer to them but never touches them. If the transverse axis of your hyperbola is horizontal, the slopes of your asymptotes are + or - b/a. If the transverse axis is vertical, the slopes are + or - a/b. The center of a hyperbola is (h,k). I don't know what the rest of your questions are, though.
The transverse axis connects what?
The transverse axis is a connection on a hyperbola. It connects the focus, or center, of the hyperbola, and can connect two together.
What is the hyperbola's point halfway between its two vertices?
Center
How do you write the equation of a circle?
The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius
What is the point halfway between its two vertices?
The center of a hyperbola is the point halfway between its foci. A hyperbola is defined as a symmetrical open curve formed by the intersection of a circular cone with a plane at a smaller angle with its axis than the side of the cone.
What is an eccentric circle?
For Ellipse: The 2 circles made using the the ellipse center as their center, and major and minor axis of the ellipse as the dia.For Hyperbola: 2 Circles with centers at the center of symmetry of the hyperbola and dia as the transverse and conjugate axes of the hyperbolaRead more: eccentric-circles
What is the equation for a hyperbola with transverse axis of length 24 and centered at the origin?
The standard form of the equation of a hyperbola with center at the origin isx2/a2 - y2/b2 = 1 where the transverse axis lies on the x-axis,ory2/a2 - x2/b2 = 1 where the transverse axis lies on the y-axis.The vertices are a units from the center and the foci are c units from the center.For both equations, b2 = c2 - a2. Equivalently, c2 = a2 + b2.Since we know the length of the transverse axis (the distance between the vertices), we can find the value of a (because the center, the origin, lies midway between the vertices and foci).Suppose that the transverse axis of our hyperbola lies on the x-axis.Then, |a| = 24/2 = 12So the equation becomes x2/144 - y2/b2 = 1.To find b we need to know what c is.
The ellipse graphed below has its center at -14-10 its horizontal axis is of length 12 and its vertical axis is of length 16 What is its equation?
(x+14)2 + (y+10)2 = 1 62 82
What is the equation of a circle with radius 10 and center -3 and 6?
Equation of a circle is given by: (x-a)2 + (y-b)2 = r2 Here a & b are the coordinates of the center. So, a = -3 & b = 6. And r = 10. Thus, the equation formed is (x+3)2+(y-6)2 = 102
