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answer for (x+5)^2/11^2-(y+16)^2/6^2=1

answer for that Question is (-5,-16)

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How do you write the generic equation suggested by a graph showing a hyperbola?

To write the generic equation of a hyperbola suggested by a graph, first identify the orientation of the hyperbola (horizontal or vertical) based on its shape. The standard forms are ((x - h)^2/a^2 - (y - k)^2/b^2 = 1) for a horizontal hyperbola and ((y - k)^2/a^2 - (x - h)^2/b^2 = 1) for a vertical hyperbola, where ((h, k)) is the center, and (a) and (b) are distances that determine the shape. Use points on the graph to find the values of (h), (k), (a), and (b) to complete the equation.


The ellipse graphed below has its center at -2 2 its horizontal axis is of length 6 and its vertical axis is of length 10 What is its equation?

23


What are the coordinates of the center of the circle described by the equation x2 y 52 16?

The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.


The transverse axis connects what?

The transverse axis is a connection on a hyperbola. It connects the focus, or center, of the hyperbola, and can connect two together.


The equation below describes a circle. What are the coordinates of the center of the circle (x - 6)2 plus (y plus 5)2 152?

The equation of the circle is given by ((x - 6)^2 + (y + 5)^2 = 152). The general form of a circle's equation is ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. From the equation, the coordinates of the center of the circle are ((6, -5)).

Related Questions

What are the coordinates of the center of the ellipse graphed by the equation below?

Answers provided by: apexvs.com (x+26)2 + (y-11)2 = 1 _____ _____ 732 7 (-26, 11) or 4


What is the length of letus rectum of hyperbola?

The length of the latus rectum of a hyperbola is given by the formula ( \frac{2b^2}{a} ), where ( a ) is the distance from the center to the vertices and ( b ) is the distance from the center to the co-vertices. This length represents the width of the hyperbola at the points where it intersects the corresponding directrices. For hyperbolas oriented along the x-axis or y-axis, this formula applies similarly, with the values of ( a ) and ( b ) depending on the specific equation of the hyperbola.


What is the term of two lines crossing the center of a graph if its a hyperbola?

The axes of the hyperbola.


How do you write the generic equation suggested by a graph showing a hyperbola?

To write the generic equation of a hyperbola suggested by a graph, first identify the orientation of the hyperbola (horizontal or vertical) based on its shape. The standard forms are ((x - h)^2/a^2 - (y - k)^2/b^2 = 1) for a horizontal hyperbola and ((y - k)^2/a^2 - (x - h)^2/b^2 = 1) for a vertical hyperbola, where ((h, k)) is the center, and (a) and (b) are distances that determine the shape. Use points on the graph to find the values of (h), (k), (a), and (b) to complete the equation.


The ellipse graphed below has its center at -2 2 its horizontal axis is of length 6 and its vertical axis is of length 10 What is its equation?

23


What are the coordinates of the center of the circle described by the equation x2 y 52 16?

The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.


What are the followings-hyberbola-asymptotes of hyperbola-centre of hyperbola-conjugated diameter of hyperbola-diameter of hyperbola-directrices of hyperbola-eccentricity of hyperbola?

Asymptotes are the guidelines that a hyperbola follows. They form an X and the hyperbola always gets closer to them but never touches them. If the transverse axis of your hyperbola is horizontal, the slopes of your asymptotes are + or - b/a. If the transverse axis is vertical, the slopes are + or - a/b. The center of a hyperbola is (h,k). I don't know what the rest of your questions are, though.


The transverse axis connects what?

The transverse axis is a connection on a hyperbola. It connects the focus, or center, of the hyperbola, and can connect two together.


The equation below describes a circle. What are the coordinates of the center of the circle (x - 6)2 plus (y plus 5)2 152?

The equation of the circle is given by ((x - 6)^2 + (y + 5)^2 = 152). The general form of a circle's equation is ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. From the equation, the coordinates of the center of the circle are ((6, -5)).


What is the center of the following circle Imported Asset?

To determine the center of a circle, you typically need the equation of the circle, which is usually in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) represents the center coordinates and (r) is the radius. If you have specific coordinates or an equation for the circle labeled as "Imported Asset," please provide that information for a more accurate answer. Otherwise, the center is found at the point ((h, k)) derived from the equation.


What is the hyperbola's point halfway between its two vertices?

Center


How do you write the equation of a circle?

The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius