answer for (x+5)^2/11^2-(y+16)^2/6^2=1
answer for that Question is (-5,-16)
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The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.
The transverse axis is a connection on a hyperbola. It connects the focus, or center, of the hyperbola, and can connect two together.
The equation of the circle is given by ((x - 6)^2 + (y + 5)^2 = 152). The general form of a circle's equation is ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. From the equation, the coordinates of the center of the circle are ((6, -5)).
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
Answers provided by: apexvs.com (x+26)2 + (y-11)2 = 1 _____ _____ 732 7 (-26, 11) or 4
The axes of the hyperbola.
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The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.
Asymptotes are the guidelines that a hyperbola follows. They form an X and the hyperbola always gets closer to them but never touches them. If the transverse axis of your hyperbola is horizontal, the slopes of your asymptotes are + or - b/a. If the transverse axis is vertical, the slopes are + or - a/b. The center of a hyperbola is (h,k). I don't know what the rest of your questions are, though.
The transverse axis is a connection on a hyperbola. It connects the focus, or center, of the hyperbola, and can connect two together.
The equation of the circle is given by ((x - 6)^2 + (y + 5)^2 = 152). The general form of a circle's equation is ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. From the equation, the coordinates of the center of the circle are ((6, -5)).
Center
The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
The center of a hyperbola is the point halfway between its foci. A hyperbola is defined as a symmetrical open curve formed by the intersection of a circular cone with a plane at a smaller angle with its axis than the side of the cone.
For Ellipse: The 2 circles made using the the ellipse center as their center, and major and minor axis of the ellipse as the dia.For Hyperbola: 2 Circles with centers at the center of symmetry of the hyperbola and dia as the transverse and conjugate axes of the hyperbolaRead more: eccentric-circles