The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.
Center of circle: (6, 8) Radius of circle: 3
The center of a 200-foot radius is the point that is exactly 200 feet away from any point on the circumference of the circle. If you visualize a circle, the center is the point from which all points on the circle are equidistant. This center point can be described by its coordinates, depending on the specific location of the circle.
I assume you mean (x-7)^2 + (y + 6)^2 = 100 (using "^" for powers). Answers.com eliminates some signs, such as the equal sign. This equation is in a form in which you can (almost) read off this information directly. A circle with equation (x - a)^2 + (y - b)^2 = r^2 has a center (a, b), and a radius of "r". In this case, just convert the original equation to: (x - 7)^2 + (y - (-6))^2 = 10^2 And you can directly read off the coordinates of the center (7, -6), and of the radius (10).
I think it is center: (-4, 3) ; radius: 2 Apex:)
The standard equation for a circle centered at the origin (0, 0) with radius ( r ) is given by ( x^2 + y^2 = r^2 ). In this equation, ( x ) and ( y ) represent the coordinates of any point on the circle, and ( r ) is the radius. This equation describes all points that are a distance ( r ) from the center.
The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius
Center of circle: (6, 8) Radius of circle: 3
The center of a 200-foot radius is the point that is exactly 200 feet away from any point on the circumference of the circle. If you visualize a circle, the center is the point from which all points on the circle are equidistant. This center point can be described by its coordinates, depending on the specific location of the circle.
There are probably several ways to approach it; one general equation for the circle is: (x - a)2 + (y - b)2 = r2 This describes a circle with center at coordinates (a, b), and with a radius of r.
The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.
The answer depends on what information is available and in what form.The simplest solution is to write the equation of the circle in the following form:(x - a)^2 + (y - b)^2 = r^2Hiving done that, the coordinates of the centre are (a, b), and the circle's radius is r.
Equation of a circle is given by: (x-a)2 + (y-b)2 = r2 Here a & b are the coordinates of the center. So, a = -3 & b = 6. And r = 10. Thus, the equation formed is (x+3)2+(y-6)2 = 102
I assume you mean (x-7)^2 + (y + 6)^2 = 100 (using "^" for powers). Answers.com eliminates some signs, such as the equal sign. This equation is in a form in which you can (almost) read off this information directly. A circle with equation (x - a)^2 + (y - b)^2 = r^2 has a center (a, b), and a radius of "r". In this case, just convert the original equation to: (x - 7)^2 + (y - (-6))^2 = 10^2 And you can directly read off the coordinates of the center (7, -6), and of the radius (10).
I think it is center: (-4, 3) ; radius: 2 Apex:)
In the algebraic equation for a circle. (x - g)^2 + (y - h)^2 = r^2 'g' & 'h' are the centre of rotation.
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
An ellipse is described as [ (x/A)2 + (y/B)2 = C2 ] If [ A=B ] then the ellipse is a circle.