The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
2y = 4x + 3At the x-intercept, y=0.0 = 4x + 34x = -3x = -3/4The coordinates of the point are (-3/4 , 0)
The x-intercept is (15 0)
The y intercept will be where the x-coordinate is zero, so set x=0 in the equation and you have: 0 + y = -9, or y = -9. Coordinate (0,-9)
Solving the equation for "y" gives you the slope-intercept form.
b
2y = 4x + 3At the x-intercept, y=0.0 = 4x + 34x = -3x = -3/4The coordinates of the point are (-3/4 , 0)
The x-intercept is (15 0)
The y intercept will be where the x-coordinate is zero, so set x=0 in the equation and you have: 0 + y = -9, or y = -9. Coordinate (0,-9)
Solving the equation for "y" gives you the slope-intercept form.
b
It is 18 and the y intercept is 3
When finding the y-intercept, plug in x=0 y = 4x + 2 y = 4(0) + 2 y = 2 So your intercept is (0,2)
x+2y=8 The x-intercept is the value of x when y=0, therefore substitute y=0 into the equation: x+0=8 therefore, x=8 The coordinates of this point is (8,0)
in the equation: y=mx+b , the y-intercept is represented by "b".
Yes, that is the slope intercept form of the equation for a straight line.
The y intercept is 6
(5, 0)