15x3
Area = 3x15=45
Perimeter = 3+3+15+15 = 36
This is solved algebraically by substituting the value of the length in terms of the width
2L + 2W = 36
L = 18-W
L x W = 45 and (18-W) x W = 45
gives the equation
W2+18W-45 = 0
(W-15)(W-3) = 0 and the width and length are 15 and 3
It is 36 ft * 2 ft - a very unlikely shape for a garden!
If the area of the garden is 81 square feet and the perimeter is 36 feet, the solution is that the garden is a square 9 feet x 9 feet, where 4 x (side) =36.
This question needs a serious spell check. It then needs a serious edit to make clear what it is asking!
Multiply the two dimension to get area. The answer would be 2,736 square feet.
The perimeter of a square is 4 times its sides. So a square garden with a length of 9 feet has a perimeter of 4*9 = 36 feet.
Possibly 9 feet by 9 feet.
24 inches * 36 feet = 2 feet * 36 feet = 72 square feet.24 inches * 36 feet = 2 feet * 36 feet = 72 square feet.24 inches * 36 feet = 2 feet * 36 feet = 72 square feet.24 inches * 36 feet = 2 feet * 36 feet = 72 square feet.
To find dimensions that equal 1291 square feet, you can consider various pairs of length and width values. For example, a rectangular area could be 37 feet by approximately 34.9 feet (since 37 x 34.9 ≈ 1291). Alternatively, if you want a square-like dimension, each side would be about 36 feet (since 36 x 36 = 1296, which is close but slightly over). Different combinations can yield various dimensions, depending on the shape.
4*9 = 36 square feet.4*9 = 36 square feet.4*9 = 36 square feet.4*9 = 36 square feet.
36 feet x 16 feet = 576 square feet.
36 x 36 = 1,296 -> 1,296 square feet on the floor -> 1,296 square feet on the ceiling -> (144 x height of the room) square feet on the walls
36*9 = 324 square feet