Let the width be x and the length be y
So: 2x+2y = 5x implying that y = 1.5x
If: xy = 130 and 2/3
Then: x(1.5x) = 130 and 2/3 => 1.5x squared = 130 and 2/3
Divide both sides by 1.5 and then square root both sides: x = 9 and 1/3 cm
Length: 130 and 2/3 divided by 9 and 1/3 = 14 cm
Therefore: length = 14 cm and width = 9 and 1/3 cm
There is no limit to the size of the perimeter.
Length = 9 Width = 9 Your rectangle is a square.
The dimensions of the rectangle are 5 cm by 4 cm
The dimensions work out as 7 units and 15 units
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
There is no limit to the size of the perimeter.
Length = 9 Width = 9 Your rectangle is a square.
Type your answer here... give the dimensions of the rectangle with an are of 100 square units and whole number side lengths that has the largest perimeter and the smallest perimeter
The dimensions of the rectangle are 5 cm by 4 cm
It is 5 units * 20 units. A smaller perimeter can be attained by a square but the question specified a rectangle.
The dimensions work out as 7 units and 15 units
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
4 x 24
Width = 3 Length = 34
The greatest area that a rectangle can have is, in fact, attained when it is a square. A square with perimeter of 16 cm must have sides of 4 cm and so an area of 4*4 = 16 cm2.