The greatest area that a rectangle can have is, in fact, attained when it is a square. A square with perimeter of 16 cm must have sides of 4 cm and so an area of 4*4 = 16 cm2.
It's greatest possible perimeter: 1+39+1+39 = 80 feet
L + W >= 24, L = W + 4, Possible dimensions 14 and 10 giving an area of 140 sq cm.
No it is not possible the dimensions are 200 by 1/2
Your question cannot be answered. An area of 14 acres is equivalent to 609,840 square feet, but a rectangle with that area could be 609,840 feet by 1 foot, or it could be 1089 feet by 560 feet, or many other possible dimensions, each of which would have a different perimeter.
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
It's greatest possible perimeter: 1+39+1+39 = 80 feet
42 square units.
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
81 square feet.
42.25 cm2
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
12.25 sq metres.
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
7 x 19 cm
L + W >= 24, L = W + 4, Possible dimensions 14 and 10 giving an area of 140 sq cm.
If the dimensions are restricted to whole numbers, then the only possibilities are 1 x 4 and 2 x 3.
No it is not possible the dimensions are 200 by 1/2