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What are the dimensions of a rectangle whose length is twice and 9 inches greater than its width and has an area of 35 sq feet?
Wiki User
∙ 13y ago
The dimensions are 8.75 ft by 4 ft because (2*4)+0.75 = 8.75 and 8.75*4 = 35 sq ft.
Note that 9 inches = 0.75 ft
Wiki User
∙ 13y ago
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