Length of rectangle garden is 5 m greater than the width. the area is 84 m2. find the dimensions of the garden.
The area of a rectangular garden is length * width. You have 200 = Length * 20, and so Length = 10 metres. Conventionally, for a rectangle, the length is the longer of the two dimensions, though for a garden, it is often the distance from the back of the house to the end of the garden that is referred to as the length - even if it is the shorter dimension.
101
Ah, what a lovely garden you have! To find the perimeter, we need to know the dimensions of the garden. If it's a square garden, we can find the side length by taking the square root of the area. Then, we can multiply the side length by 4 to get the perimeter. Happy painting those beautiful flowers and trees in your garden!
It is 36 ft * 2 ft - a very unlikely shape for a garden!
Length of garden = 2 times its width plus 5 feet Let 2x+5 = length and let x = width Area of sidewalk = 6x = 213 square feet x = 35.5 feet which is the width of the garden 2*35.5+5 = 76 feet which is the length of the garden
The area of a rectangular garden is length * width. You have 200 = Length * 20, and so Length = 10 metres. Conventionally, for a rectangle, the length is the longer of the two dimensions, though for a garden, it is often the distance from the back of the house to the end of the garden that is referred to as the length - even if it is the shorter dimension.
What do you mean by "largest" ??? Do you want the widest rectangle ? The longest rectangle ? How about the rectangle with the most area ? The length can be anything less than 20 ft, and the width can be anything less than 20 ft. Any of those shapes will have an area greater than zero. The rectangular garden with the greatest possible area is a square, 10 ft x 10 ft. Its area is 100 square feet.
no because the square's length is bigger than the rectangle's length
The dimensions are 12 feet by 4 feet
You CAN'T calculate the surface area of a rectangle, given only its perimeter. The answer varies, depending on the length-to-width ratio of the rectangle. Thus, you would need some additional information; for example one of the following:* The length * The width * The length-to-width ratio * The length of the diagonal * Some other data that will let you calculate the remaining information about the rectangle.
length = 22 meters and width = 6 meters
9 x 8
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divide perimeter by 6.
Let the width of the garden be ( w ) feet. Then the length can be expressed as ( 2w - 4 ) feet. The perimeter of a rectangle is given by the formula ( P = 2(\text{length} + \text{width}) ). Setting up the equation, we have ( 2((2w - 4) + w) = 52 ), which simplifies to ( 3w - 4 = 26 ). Solving for ( w ), we find ( w = 10 ) feet.
Let the length be 2x-3 and the width be x:- So: 2*(2x-3+x) = 82 feet => 6x-6 = 82 => x = 14 and 2/3 Therefore the dimensions are: length = 26 ft 4 ins and width = 14 ft 8 ins
To find the possible dimensions of a rectangular garden using 40 feet of fencing, we can use the formula for the perimeter of a rectangle: ( P = 2 \times (length + width) ). Setting the perimeter to 40 feet gives us the equation ( length + width = 20 ). Therefore, for any integer value of the length (from 1 to 19 feet), the width can be calculated as ( width = 20 - length ). Possible pairs of dimensions include (1, 19), (2, 18), (3, 17), and so on, up to (19, 1).