In general, the Laplace operator in n dimensions is
∇2 = (∂/∂x1)2 + (∂/∂x2)2 + ... + (∂/∂xn)2,
and the eigenfunctions are the solutions f(x1, x2, ..., xn) of the partial differential equation:
∇2f = -λf,
where the eigenvalues -λ are to be determined. Often, the set of solutions will be constrained by given boundary conditions (which limits the possible values of λ), but for the purposes of this question that does not matter.
In one dimension this gives a simple linear differential equation with constant coefficients:
d2f/dx2 = -λf
which may be solved using standard, elementary techniques. For λ > 0 the solutions may be written:
f(x) = A cos((√λ) x) + B sin((√λ) x)
and for λ < 0:
f(x) = A exp((√-λ) x) + B exp(-(√-λ) x)
where in each case A and B are arbitrary constants. Using Euler's formula
exp(ia) = cos(a) + i sin(a)
the solutions in both cases can be written as linear combinations of the exponential functions exp((±i√λ) x).
In the case that λ = 0, the solutions are straight lines:
f(x) = Ax + B.
The Dirac delta function.
I love 1d I hate everyone who hates 1d apart from my boyfriend and my friends
The answer is Louis Tomlinson.
Operon. It contains the promoter, operator, and the structural gene.
A repressor protein turns off transcription by binding to the operator region. By binding to the operator, the repressor prevents the RNA polymerase from binding to the promoter region and initiating transcription. This prevents the expression of the gene or genes downstream of the operator.
Steven Zelditch has written: 'Selberg trace formulae and equidistribution theorems for closed geodesics and Laplace eigenfunctions' -- subject(s): Curves on surfaces, Cusp forms (Mathematics), Eisenstein series, Geodesics (Mathematics)
He formulated Laplace's equation, and invented the Laplace transform which appears in many branches of mathematical physics, a field that he took a leading role in forming. The Laplacian differential operator, widely used in applied mathematics, is also named after him.
Work in Celestial Mechanics Laplace's equation Laplacian Laplace transform Laplace distribution Laplace's demon Laplace expansion Young-Laplace equation Laplace number Laplace limit Laplace invariant Laplace principle -wikipedia
yes
Laplace equation: in 3D U_xx+U_yy+U_zz=0 Or in 2D U_xx+U_yy=0 where U is a function of the spatial variables x,y,z in 3D and x,y in 2D.Also, U_xx is the second order partial derivative of u with respect to x, same for y and z. Laplace transform: L(f(t))=integral of (e^(-s*t))*f(t) dt as t goes from 0 to infinity. Laplace transform is more like an operator rather than an equation.
A Hermitian operator is any linear operator for which the following equality property holds: integral from minus infinity to infinity of (f(x)* A^g(x))dx=integral from minus infinity to infinity of (g(x)A*^f(x)*)dx, where A^ is the hermitian operator, * denotes the complex conjugate, and f(x) and g(x) are functions. The eigenvalues of hermitian operators are real and their eigenfunctions are orthonormal.
A Laplace transform is a mathematical operator that is used to solve differential equations. This operator is also used to transform waveform functions from the time domain to the frequency domain and can simplify the study of such functions. For continuous functions, f(t), the Laplace transform, F(s), is defined as the Integral from 0 to infinity of f(t)*e-stdt. When this definition is used it can be shown that the Laplace transform, Fn(s) of the nth derivative of a function, fn(t), is given by the following generic formula:Fn(s)=snF(s) - sn-1f0(0) - sn-2f1(0) - sn-3f2(0) - sn-4f3(0) - sn-5f4(0). . . . . - sn-nfn-1(0)Thus, by taking the Laplace transform of an entire differential equation you can eliminate the derivatives of functions with respect to t in the equation replacing them with a Laplace transform operator, and simple initial condition constants, fn(0), times a new variable s raised to some power. In this manner the differential equation is transformed into an algebraic equation with an F(s) term. After solving this new algebraic equation for F(s) you can take the inverse Laplace transform of the entire equation. Since the inverse Laplace transform of F(s) is f(t) you are left with the solution to the original differential equation.
Laplace will only generate an exact answer if initial conditions are provided
Pierre- Simon de Laplace
Laplace no Ma happened in 1987.
Charles Laplace died in 2008.
Víctor Laplace was born in 1943.