answersLogoWhite

0

Laplace will only generate an exact answer if initial conditions are provided

User Avatar

Wiki User

12y ago

Still curious? Ask our experts.

Chat with our AI personalities

ProfessorProfessor
I will give you the most educated answer.
Chat with Professor
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa
MaxineMaxine
I respect you enough to keep it real.
Chat with Maxine
More answers

What are the limitations of Laplace transform

User Avatar

Add your answer:

Earn +20 pts
Q: What are the limitations of laplace transform?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Other Math

What was the Laplace transform of sin2 3t?

the Laplace transform of sin2 3thttp://www7.0zz0.com/2009/12/30/19/748450027.gif


What is the Laplace transform of doublet function?

s


What is the Laplace transform of the signum function?

2/s


Laplace transform of 1?

LaplaceTransform [1, t, s] = 1/s


What is Laplace transform?

A Laplace transform is a mathematical operator that is used to solve differential equations. This operator is also used to transform waveform functions from the time domain to the frequency domain and can simplify the study of such functions. For continuous functions, f(t), the Laplace transform, F(s), is defined as the Integral from 0 to infinity of f(t)*e-stdt. When this definition is used it can be shown that the Laplace transform, Fn(s) of the nth derivative of a function, fn(t), is given by the following generic formula:Fn(s)=snF(s) - sn-1f0(0) - sn-2f1(0) - sn-3f2(0) - sn-4f3(0) - sn-5f4(0). . . . . - sn-nfn-1(0)Thus, by taking the Laplace transform of an entire differential equation you can eliminate the derivatives of functions with respect to t in the equation replacing them with a Laplace transform operator, and simple initial condition constants, fn(0), times a new variable s raised to some power. In this manner the differential equation is transformed into an algebraic equation with an F(s) term. After solving this new algebraic equation for F(s) you can take the inverse Laplace transform of the entire equation. Since the inverse Laplace transform of F(s) is f(t) you are left with the solution to the original differential equation.