They are 2, 3 and 5
It is 126.
To tackle this question, you first need to break the number down into its prime factors. In this case we have 64 = 2x2x2x2x2x2 To find the greater factors, you need to multiply any combination of these. That gives us the factors as 2, 4, 8, 16, 32 and 64 Adding these up for the sum gives us 126 Thus the sum of all even factors of 64 is 126.
The factors of 64 are 1, 2, 4, 8, 16, 32 and 64
64 is a composite number. A prime number has exactly two factors, 1 and the number itself, and no even number greater than 2 is a prime. The factors of 64 are 1, 2, 4, 8, 16, 32, and 64.
The factors of 27 are 1,3,9, and 27 The factors of 64 are 1,2,4,8,16,32, and 64. 1 is the only common factor of 27 and 64.
The factors of 64 are 1, 2, 4, 8, 16, 32, and 64.
The Factors of 64 are 1, 2, 4, 8, 16, 32 and 64.
The factors of 64 are 1, 2, 4, 8, 16, 32, and 64.
The factors to 64 are: 1, 2, 4, 8, 16, 32, 64.
To break a number down into prime factors, it is best to divide it by the obvious divisors first. In this case, 64 is even so can be divided by 2. If this is done, you get 32, which is also even. Divide by 2 again produces 16, which is known from times tables to be 4x4, and each of these 4s can be broken down into 2x2. Thus, the prime factors of 64 are 2, 2, 2, 2, 2 and 2. As a product of its prime factors, 64 is 2x2x2x2x2x2
Factors for 64 are: 1, 2, 4, 8, 16, 32, 64
The factors of 64 are: 1, 2, 4, 8, 16, 32, 64.