To break a number down into prime factors, it is best to divide it by the obvious divisors first. In this case, 64 is even so can be divided by 2. If this is done, you get 32, which is also even. Divide by 2 again produces 16, which is known from times tables to be 4x4, and each of these 4s can be broken down into 2x2. Thus, the prime factors of 64 are 2, 2, 2, 2, 2 and 2. As a product of its prime factors, 64 is 2x2x2x2x2x2
As a product of its prime factors: 2*2*2*2*2*2 = 64 or in exponent 2^6 = 64
As product of its prime factors in exponent terms: 2^6 = 64
The only prime factor of 64 is 2.
The only prime factor of 64 is 2.
Multiply prime numbers or prime factors to find their product.
64 = 26
As a product of its prime factors: 2*2*2*2*2*2 = 64 or in exponent 2^6 = 64
It is 2*2
As product of its prime factors in exponent terms: 2^6 = 64
Just the one and it is 2 but as a product of its prime factors: 2*2*2*2*2*2 = 64
As a product of its prime factors: 2*2*2*2*2*2 = 64 or as 26 = 64
As a product of its prime factors: 2311 = 66
63 does not have fewest prime factors. It is a product of 3, 3 and 7.
The only prime factor of 64 is 2.
64 = 2x2x2x2x2x2
This Question needs to be answered in a few steps. The first step is to split each number into a product of its prime factors. 64 as a product of its prime factors = 2^6 96 as a product of its prime factors = 2^5*3 The LCM will be written as a product of the largest instances of the indices in each unit above. LCM = 2^6*3 = 192 This should be correct, but it is always good to check. 192/64 = 3; 192/96 = 2, so this answer is plausible. It is: 192
Prime factor is 2. Factors are 1, 2, 4, 8, 16, 32, 64