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What else can I help you with?
A. 4x5 b.2x2x5 c.2x10. which is the prime factors?
b. 2x2x5 are prime factors
How do you use the prime factorizations to find the LCM of a and b?
a and b have no common prime factors. Their LCM is their product.
What are the factors and prime factors of 56a2b2?
I wonder if you mean 56a2b2 ? If so you have 2 x 2 x 2 x 7 x a x a x b x b. If a and/or b are not prime, you will have the factors of those as well.
What is the difference between factors and prime factors?
A factor of a integer is an integer that divides the second integer into a third integer exactly; i.e. A is a factor of B if B/A is exactly C, where all of A, B and C are integers. A prime factor is a factor as above, but is also a prime number. This means that the only factors of that factor are one and the number itself; i.e. A is a prime factor of B if B/A is exactly C andthe only factors of A are 1 and A.
Which number has exactly 10 factors?
Any number of the form a*b^4 where a and b are different prime numbers, or c^9 where c is a prime, will have exactly 10 factors.
What are the prime number b?
A prime number is a number that has only two factors which are itself and one.
What are the common factors and prime factors for B and C?
Variables can be any number, which leaves an infinite possibility of factors.
What is the greatest common factor of 42a2b and 60ab2?
To find the greatest common factor (GCF) of 42a^2b and 60ab^2, we first need to break down each term into its prime factors. For 42a^2b, the prime factors are 2 * 3 * 7 * a * a * b. For 60ab^2, the prime factors are 2 * 2 * 3 * 5 * a * b * b. Comparing the prime factors of both terms, we can identify the common factors: 2, 3, a, and b. Therefore, the GCF of 42a^2b and 60ab^2 is 6ab.
Which is a prime numberWhich is a prime number A 21 B 31 C 57 D 91?
It is: B 31 is a prime number because it has only two factors which are itself and one
Determine which is not a prime factor of 70 A.2 B.5 C.7 D.10?
10 is not prime and can't be a prime factor.
Give a proof that the square root of 7 is an irrational number?
Proof by contradiction: suppose that root 7 (I'll write sqrt(7)) is a rational number, then we can write sqrt(7)=a/b where a and b are integers in their lowest form (ie they are fully cancelled). Then square both sides, you get 7=(a^2)/(b^2) rearranging gives (a^2)=7(b^2). Now consider the prime factors of a and b. Their squares have an even number of prime factors (eg. every prime factor of a is there twice in a squared). So a^2 and b^2 have an even number of prime factors. But 7(b^2) then has an odd number of prime factors. But a^2 can't have an odd and an even number of prime factors by unique factorisation. Contradiction X So root 7 is irrational.
How are prime factors and factors related?
Prime factors are factors that are also prime numbers.
