Variables can be any number, which leaves an infinite possibility of factors.
Alright, buckle up, buttercup. To find the least common multiple of 10ab and 14abc, you need to break down both numbers into their prime factors. The prime factors of 10ab are 2 * 5 * a * b, while the prime factors of 14abc are 2 * 7 * a * b * c. Now, the least common multiple will be the product of all the unique prime factors with the highest power they appear in either number. So, the least common multiple of 10ab and 14abc is 2 * 5 * 7 * a * b * c. Hope that clears things up for ya!
A factor of a integer is an integer that divides the second integer into a third integer exactly; i.e. A is a factor of B if B/A is exactly C, where all of A, B and C are integers. A prime factor is a factor as above, but is also a prime number. This means that the only factors of that factor are one and the number itself; i.e. A is a prime factor of B if B/A is exactly C andthe only factors of A are 1 and A.
To factorize the expression abxb + acxc, we first identify the common factors in each term. In this case, the common factors are b in the first term and c in the second term. We then factor out these common factors to get b(a + x) + c(a + x). Finally, we factor out the common binomial factor of (a + x) to get (a + x)(b + c) as the fully factorized expression.
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Prime triple definition: Assume that a<b<c. a, b, and c form a prime triple just if both of the pairs (a,b) and (b, c) are twin primes.
b. 2x2x5 are prime factors
the only common factor is 1 b/c 11 is a prime number.
Alright, buckle up, buttercup. To find the least common multiple of 10ab and 14abc, you need to break down both numbers into their prime factors. The prime factors of 10ab are 2 * 5 * a * b, while the prime factors of 14abc are 2 * 7 * a * b * c. Now, the least common multiple will be the product of all the unique prime factors with the highest power they appear in either number. So, the least common multiple of 10ab and 14abc is 2 * 5 * 7 * a * b * c. Hope that clears things up for ya!
Any number of the form a*b^4 where a and b are different prime numbers, or c^9 where c is a prime, will have exactly 10 factors.
A factor of a integer is an integer that divides the second integer into a third integer exactly; i.e. A is a factor of B if B/A is exactly C, where all of A, B and C are integers. A prime factor is a factor as above, but is also a prime number. This means that the only factors of that factor are one and the number itself; i.e. A is a prime factor of B if B/A is exactly C andthe only factors of A are 1 and A.
If the greatest common factor/divisor of A and B is 1 then they are coprime - they do not share any prime factors. Multiplying both through by C means, obviously, that each number now divides by C. In fact, C is their greatest common divisor, since AC and BC do not have further common factors after C is taken out. Hence the GCF of AC and BC is not merely a factor of C - it is C. (The question makes sense only if A, B and C are integers.)
134
To factorize the expression abxb + acxc, we first identify the common factors in each term. In this case, the common factors are b in the first term and c in the second term. We then factor out these common factors to get b(a + x) + c(a + x). Finally, we factor out the common binomial factor of (a + x) to get (a + x)(b + c) as the fully factorized expression.
The greatest factors of A, B, and C, respectively, are the absolute values of A, B, and C. The greatest common factor of A, B, and C is 1.
It is: B 31 is a prime number because it has only two factors which are itself and one
As a product of its prime factors: 3*3*3*3 = 81 and 4*3 = 12
If it's just factors, then any number have an even amount of factors. Let a be any number, a = 1 a so a have two factors, 1 and a. Two is even. But if the question is what number have an even amount of PRIME factors, then it is different. Because if a is not prime, the might exist another two numbers b and c != 1 such that a = b c. and also, b is not prime, b = d e So a = bc = de c = c d e So a have three prime factors (1 is not prime for some reason) Then this question is less trivial: 6 have only prime factor 2 and 3, 10 only have prime factor 2 and 5, they are even. but 9 only have prime factor 3, so it's not an even amount, so 9 is not.