7 and -6
1 + 2 + 4 + 5 + 10 + 20 = 42
Hint: review your multiplication table-- does not 42 ring a bell? What times what makes 42? Is their sum 13? ?? bingo!!
42 has three prime factors: 2, 3 and 7
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42=2*3*7 2+3+7 = 12
The factors of 3 are 1 and 3. The sum of the digits of these factors is calculated as follows: for 1, the sum of its digits is 1, and for 3, the sum of its digits is 3. Therefore, the total sum of the digits of the factors of 3 is 1 + 3 = 4.
It is only possible to have one even prime factor of any number - as there is only one even prime number, 2. The sum of these is therefore 2.
2 + 5 + 10 + 25 = 42
The factors of 7 are 1, 7. The factors of 42 are 1, 2, 3, 6, 7, 14, 21, 42.
GCF(7, 42) = 77 = 7*1 and 42 = 7*6 So 7 + 42 = 7*(1 + 6).
There are no two numbers that multiply to 42 and add up to 8. The pairs of factors of 42, such as (1, 42), (2, 21), (3, 14), and (6, 7), do not sum to 8. Therefore, it is not possible to find such numbers.
The common factors of 42 and 273 are 1, 3, 7 and 21.