1, 2, 5, 10, 29, 58, 145, 290
1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 128, 192, 384
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384 has 16 factors.
The positive integer factors of 290 are: 1, 2, 5, 10, 29, 58, 145, 290
The factors of 290 are: 1, 2, 5, 10, 29, 58, 145, 290.
2 and 3
As a general rule, factors cannot be larger than the number they are compared to. 384 is a multiple of 96. 96 is a factor of 384.
As a product of its prime factors in exponents: 27*3 = 384
290 is a composite number because it has factors other than 1 and itself. It is not a prime number.The eight factors of 290 are 1, 2, 5, 10, 29, 58, 145, and 290.The factor pairs of 290 are 1 x 290, 2 x 145, 5 x 58, and 10 x 29.The proper factors of 290 are 1, 2, 5, 10, 29, 58, and 145 or,if the definition you are using excludes 1, they are 2, 5, 10, 29, 58, and 145.The prime factors of 290 are 2, 5, and 29.The three distinct prime factors (listing each prime factor only once) of 290 are 2, 5, and 29.The prime factorization of 290 is 2 x 5 x 29.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
The factors of 384 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 128, 192, 384.
(t - 24)(t + 16)
The Highest Common Factor (HCF) of 384 and 512 is the largest number that divides both 384 and 512 without leaving a remainder. To find the HCF, we first list the factors of each number: 384 factors are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 128, 192, and 384. 512 factors are 1, 2, 4, 8, 16, 32, 64, 128, 256, and 512. The largest number that appears in both lists is 64, so the HCF of 384 and 512 is 64.
As an even number greater than 2, 290 is divisible by 2 and therefore composite. Its positive integer factors are: 1, 2, 5, 10, 29, 58, 145, 290
Oh, dude, you're asking me to find numbers divisible by 384? Like, any number that ends in 384 is technically divisible by 384. So, 384, 768, 1152, and so on. But, like, who's really out there dividing by 384 anyway?