The Highest Common Factor (HCF) of 384 and 512 is the largest number that divides both 384 and 512 without leaving a remainder. To find the HCF, we first list the factors of each number: 384 factors are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 128, 192, and 384. 512 factors are 1, 2, 4, 8, 16, 32, 64, 128, 256, and 512. The largest number that appears in both lists is 64, so the HCF of 384 and 512 is 64.
hcf(324, 512) = 4 324 = 2² x 3⁴ 512 = 2⁹ hcf = 2² = 4
384
48 & 336; 144 & 240; For inf, this was calculated by dividing 384 by 48, giving 8. This means that the numbers sought are multiples of 48 by two numbers totalling 8. 1/7 and 3/5 are the only answers which fit the question as 2/6 would mean the HCF was 96 (96 and 288).
384
8937093 + 384 = 8,937,477
hcf(324, 512) = 4 324 = 2² x 3⁴ 512 = 2⁹ hcf = 2² = 4
384
The Highest Common Factor (HCF) of 336 and 384 is the largest number that divides both 336 and 384 without leaving a remainder. To find the HCF, you can use the Euclidean algorithm, which involves dividing the larger number by the smaller number, then using the remainder as the divisor in the next iteration. Continuing this process will eventually lead to a remainder of 0, at which point the divisor will be the HCF. In this case, the HCF of 336 and 384 is 48.
LCM = Product/HCF = 384
The surface area of a cube with a volume of 512 mm3 is: 384 square mm
ok what you need to do is divide 512 by 4 which equals 128 so 128 big shells and 512-128=384 so 384 small shells.... I'm eleven!
384
The least common factor of any set of integers is 1.
V = 512 units3
The surface area of this cube is 384 mm2
64, 128, 192, 256, 320, 384, 448, 512, 576, 640, 704, . . .
64, 128, 192, 256, 320, 384, 448, 512, 576, 640, 704, 768 and so on.