What are the factors of 42x3y2?

Answer 1

If you mean prime factors they are:

42x3y2 = 2*3*7*x3y2

All of the factors of it are:

1, 2, 3, 6, 7, 21, 42,

and any of those numbers multiplied by either x, x2, x3, y, y2, xy, xy2, x2y, x2y2, x3y, or x3y2.