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Q: What are the factors of 8x2 plus 2x- 1?

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8x2 + 2x - 1 = 8x2 + 4x - 2x - 1 = 4x(2x + 1) - 1(2x + 1) = (4x - 1)(2x + 1)

What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).

(4x - 1)(2x + 1)

(2x + 1)(4x + 7)

(3x - 1)(2x2 - 2x - 1)

2(2x - 1)(2x + 1)

(4x + 3)(2x - 1) so x = -0.75 or 0.5

8x2 + 16x + 8 = 8*(x2 + 2x + 1) = 8*(x + 1)2

Cross-multiplying gives: (x + 3)(3 - 2x) = (3x + 1)(2x - 1) ie -2x2 - 3x + 9 = 6x2 - x - 1 add 2x2 to each side: -3x + 9 = 8x2 - x - 1 add 3x to each side: 9 = 8x2 + 2x - 1 subtract 9 from each side: 8x2 + 2x - 10 = 0 divide by 2: 4x2 + x - 5 = 0 Factors are: (4x + 5)(x - 1) x = -1.25 or 1

8x^2 + 14x + 3 factors to (4x + 1)(2x + 3)

8x2-2x-3=0 (2x+1)(4x-3)=0 2x+1=0 or 4x-3=0 x=-1/2 or x=3/4

4x3+10x2+2x+5= (2x+5)(2x2+1)

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