(10x + 1)(x + 10)
That's not a trinomial, but it factors to x(x + 19)
(3x - 4)(x - 1)
First you express the numbers as their prime factors: 3y = 3, y y2 = y, y Next you identify any common prime factors. In this case both numbers have y as a prime factor. Finally you multiply the numbers and divide by the HCF: 3y(y2)/y = 3y2 and thus the LCM is 3y2
x2-7x-44 (x-11)(x+4)
prime
(2x + 1)(x + 3) are the factors.
-((x + 2)(x - 9))
(10x + 1)(x + 10)
-8(x - 7y)(x + 2y)
Factors are (7y - 3)(7y - 2) so it's not a perfect square.
Assuming you mean n2 + 11n + 30, the factors are (n + 6)(n + 5).
The factors of x2 + 5x + 4 would be (x + 1) and (x + 4)
That factors to (x - 14)(x - 2)
9
(8x + 5y)(64x^2 - 40xy + 25y^2)
Yes; the factored form would be (9c+4)(9c+4) or just (9c+4)2 Since the two factors are the same, the beginning trinomial 81c2+72c+16 is a perfect square trinomial