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I think that wants to be 16x2 - 40xy + 25y2

That factors to (4x - 5y)(4x - 5y) or (4x - 5y)2

Q: What the prime factors of the trinomial 16x -40xy plus 25y?

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(10x + 1)(x + 10)

That's not a trinomial, but it factors to x(x + 19)

(3x - 4)(x - 1)

First you express the numbers as their prime factors: 3y = 3, y y2 = y, y Next you identify any common prime factors. In this case both numbers have y as a prime factor. Finally you multiply the numbers and divide by the HCF: 3y(y2)/y = 3y2 and thus the LCM is 3y2

Step 1: 3(x2 + 7x - 44) Step 2: 3(x + 11)(x - 4)

Related questions

prime

(2x + 1)(x + 3) are the factors.

-((x + 2)(x - 9))

(10x + 1)(x + 10)

Factors are (7y - 3)(7y - 2) so it's not a perfect square.

-8(x - 7y)(x + 2y)

Assuming you mean n2 + 11n + 30, the factors are (n + 6)(n + 5).

The factors of x2 + 5x + 4 would be (x + 1) and (x + 4)

That factors to (x - 14)(x - 2)

9

(8x + 5y)(64x^2 - 40xy + 25y^2)

Yes; the factored form would be (9c+4)(9c+4) or just (9c+4)2 Since the two factors are the same, the beginning trinomial 81c2+72c+16 is a perfect square trinomial