x2 - 16x + 28 = x2 -2x - 14x - 28 = x(x - 2) - 14(x - 2) = (x - 14)(x - 2)
x2 - 7x = 60 x2 - 7x - 60 = 0 (x - 12) (x + 5) = 0 x = 12 or x = -5
12
x2-2x-15 = (x+3)(x-5) when factored
X2 - 16X + 15 = 0 (X - 1)(X - 15) = 0 So X -1 = 0 or X - 15 = 0 ie X = 1 or X = 15
Addd 60 to each side: x2 - 16x + 60 = 0; what two numbers multiply to 60 and add to 16? 6 and 10 look good, so... (x - 6)(x - 10) = 0 x = 6 or 10
3x3 -3x2 - 48x - 60 = 0 simply factor out a 3... 3(x3 - x2 - 16x - 20) = 0
(x - 15)(x - 1)
It is: x2-16x+60 = (x-6)(x-10) when factored
Assuming you wish to make this equation equal zero, for x2 + 16x + 55 = 0, x = -5.
to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16. These two numbers are 8 and 8. (x2-16x+64)=(x-8)(x-8)
(x - 7)(x - 9)
(the shape is an upside down 'u').
Half of the coefficient of x, squared. For example: x2 + 16x -3 you would add 8^2. Then you would have: x2 +16x +8^2 = 3-8^2 Which leads to: (x+8)^2 = -61
Y=(x+8)^2-5
x2+16x-17 = (x-1)(x+17) when factored
use the quadratic formula since there isn't a factor of 60 that when added together equals 19 The above answer is wrong because 4 and 15 are such numbers. x2 + 19x + 60 = x2 + 4x + 15x + 60 = x(x + 4) + 15(x + 4) = (x + 4)(x + 15)