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Q: What are the factors of the monomial 6ab squared?

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-2a^2

2a x 3b = 6ab

6ab(2x2+x-5)

3

yes

Common factors

No because it has 3 terms

I'm presuming its factors for a monic quadratic trinomial--of form : X squared + BX + C . You need the numbers that MULTIPLY to give C and ADD up to give B Eg X squared + 8X + 12 factors to ( X+2) (X + 6 ) BUT X squared + 7X + 12 factors to (X +3 )(X + 4) Hope this helps. Phil.

3a2b is the simplest formImproved Answer:-3a x 2b = 6ab when simplified

6(ab - ac + b2 - bc)

To find the greatest common factor (GCF) between monomials, take each monomial and write it's prime factorization. Then, identify the factors common to each monomial and multiply those common factors together. Bam! The GCF!

36

19 x a x a x b = 19a2b

19 x a x a x b = 19a2b

(x + 1) and (x + 2) are monomial factors of the polynomial x2 + 3x + 2 (x + 1) and (x + 3) are monomial factors of the polynomial x2 + 4x + 3 (x + 1) is a common monomial factor of the polynomials x2 + 3x + 2 and x2 + 4x + 3

6ab-3b factorize = 3

-1 x 7 x c x c = -7c2

Correct.

1,2,3,6,a,b,b

The greatest common factor of 4ab and 6ab is 2ab. You simply take the greatest common factor from both factors. The greatest common factor of 4 and 6 is 2. The letters can be factored out because they appear in both factors

(x + 1) and (x + 2) are monomial factors of the polynomial x2 + 3x + 2. (x + 1) and (x + 3) are monomial factors of the polynomial x2 + 4x + 3. (x + 1) is a common monomial factor of the polynomials (x2 + 3x + 2) and (x2 + 4x + 3)

5a2 + 6ab=a(5a+6b)

14xy2 would be 3 (14xy)2 would be 4

variables

0.3333

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