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To factorize the expression 4ab - 6ab, you first need to identify the common factor between the two terms, which is 2ab. You can then factor out this common factor to rewrite the expression as 2ab(2 - 3). Therefore, the fully factorized form of 4ab - 6ab is 2ab(2 - 3) or simply -2ab.
What else can I help you with?
How do you factorise 4ab-2ac?
2a(2b-c) :P
What is the greatest common factor of 4ab and 6ab?
The greatest common factor of 4ab and 6ab is 2ab. You simply take the greatest common factor from both factors. The greatest common factor of 4 and 6 is 2. The letters can be factored out because they appear in both factors
How do you factorise 6ab-9ac?
Ah, let's take a moment to appreciate the beauty of algebra. To factorise 6ab - 9ac, we can first factor out the greatest common factor, which is 3a. This leaves us with 3a(2b - 3c), where 2b - 3c is the factored expression. Just like painting a happy little tree, we've simplified our expression with a few gentle brushstrokes.
What is 5a2 6ab factorized?
5a2 + 6ab=a(5a+6b)
How do you simplify an expression in the format of 4a2 plus 4ab - y2 plus b2?
4a2 + 4ab - y2 + b2 You cannot simplify this expression because it does not contain like terms, but you can factor it such as: 4a2 + 4ab - y2 + b2 = (4a2 + 4ab + b2) - y2 = (2a + b)2 - y2 = [(2a + b) - y][(2a + b) + y]
How do you factorise 4ab?
2a(2b) Would Give You The Answer 4ab. 2x2 = 4 And a x b = ab.
How do you factorise 4ab-2ac?
2a(2b-c) :P
Find the difference (-2ab-2a-5)-(6ab plus 2)?
4ab - 2a - 7
What is the greatest common factor of 4ab and 6ab?
The greatest common factor of 4ab and 6ab is 2ab. You simply take the greatest common factor from both factors. The greatest common factor of 4 and 6 is 2. The letters can be factored out because they appear in both factors
How do you multiply 4ab and 6ab?
To multiply the expressions (4ab) and (6ab), you first multiply the coefficients (the numerical parts) and then multiply the variables. So, (4 \times 6 = 24), and for the variables, (a \times a = a^2) and (b \times b = b^2). Combining these, the product is (24a^2b^2).
12a2b plus 8a-5a2b plus 2ab - 4ab2 plus 6ab-2a-3ab?
Assuming that non-leading numbers are exponents, the expression becomes12a^2b + 8a - 5a^2b + 2ab - 4ab^2 + 6ab - 2a - 3ab= 7a^2b + 6a + 5ab - 4ab^2= a*(7ab + 6 + 5b - 4b^2)
How do you factorise 6ab-9ac?
Ah, let's take a moment to appreciate the beauty of algebra. To factorise 6ab - 9ac, we can first factor out the greatest common factor, which is 3a. This leaves us with 3a(2b - 3c), where 2b - 3c is the factored expression. Just like painting a happy little tree, we've simplified our expression with a few gentle brushstrokes.
Simplify 5a³ - 4ab plus 2a³ as much as possible?
5a³ - 4ab + 2a³ = (5+2)a³ - 4ab = 7a³ - 4ab.
2a x 2b?
Urmm 4ab ?
What is the answer for (-a-7b plus 5)4ab?
(-a-7b+5)4ab
What is 5a2 6ab factorized?
5a2 + 6ab=a(5a+6b)
What is 6ab-3b factorize?
6ab-3b factorize = 3
