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The factor pairs of 58 are 58 and 1, and 29 and 2.

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: What are the factors pairs of 58?
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Related questions

What are all the factor pairs of 58?

1 x 58 = 58 2 x 29 = 58 Therefore, factor pairs = 1 and 58, 2 and 29.


What are the factors in 58?

The factors of 58 are: 1, 2, 29, 58.


What are the factors or 58?

The factors of 58 are: 1, 2, 29, 58.


What are the factors and prime factors of 58?

58 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 4 factors of 58 are 1, 2, 29, and 58.The factor pairs of 58 are 1 x 58 and 2 x 29.The proper factors of 58 are 1, 2, and 29 or,if the definition you are using excludes 1, they are 2 and 29.The prime factors of 58 are 2 and 29.The distinct prime factors (listing each prime factor only once) of 58 are also 2 and 29.The prime factorization of 58 is 2 x 29.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common. The prime factorization of 58 is 2x29.58/2 = 2929/29 = 1


What are all the factors for the number 58?

The factors of 58 are: 1, 2, 29, 58.


Can you list all the factors of 58?

The factors of 58 are: 1, 2, 29, 58.


Are the factors of 58?

Its factors are: 1, 2, 29 and 58


How factors different from factor pairs?

Factors are single numbers. Factor pairs are listed in pairs.


What are the factors of 57 and 58?

The factors of 57 are: 1, 3, 19, 57 The factors of 58 are: 1, 2, 29, 58


What are the factors and prime factors ofΒ 58?

Factors: 1 2 29 58 Prime factors: 2*29


What is the prime number factors of 58?

2 and 29 are the prime factors of 58.


If pairs of factors separate independently of other pair factors you are dealing with?

If pairs of factors separate independently of other pairs of factors, you are dealing with the: Law of independent assortment

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