Factors: 1, 3, 9, 27. Pairs: (1,27);(3,9).
9 = 1 x 9, 3 x 3, 9 x 1
Four pairs: 54 and 1 27 and 2 18 and 3 9 and 6
1 and 18 2 and 9 3 and 6
36 does.
The answer is 18.Factors 1*18=18 Factors added 1+18=192*9=18 2+9=113*6=18 3+6=9
Factors of 81 in pairs = 1 x 81, 3 x 27, 9 x 9, 27 x 3, 81 x 1.
If pairs of factors separate independently of other pairs of factors, you are dealing with the: Law of independent assortment
The positive integer factors of 243 are 1, 3, 9, 27, 81, and 243 The factor pairs of 243 are (1, 243), (3, 81), and (9, 27).
The factors of 279 are: 1 3 9 31 93 279These pairs of numbers, when multiplied, equal 279:(1, 279)(3, 93)(9, 31)
The factors of 549 are 1, 3, 9, 61, 183, and 549The factor pairs of 549 are (549,1), (183,3), and (61,9)1,3,9,61,183,549
The factors for 18 are: 1,2,3,6,and 9