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What is the first 3 terms of 4n?
4, 8, 12
What are the first 3 terms for 4n plus 1?
As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------
What does n plus 4n-3 equals?
1
What is 4n plus 13 equals 1?
4n+13=1 -13 -134n=-12/4 /4n=-3
How would you factorise the equation 4n squared add 11n subtract 3?
4n2 + 11n - 3The following method is mathematically correct but may not be taught in school so be careful about using it.Multiply the last term by the coefficient of the first term:4n2 + 11n - 12Reduce the power of n in the first term by one and write them as the first terms in two binomial expressions:(4n )*(4n ).Find 2 factors of the last term (12), and since it is negative, the difference between these two factors should be the middle term (1 and 12). The larger of these takes the same sign as the middle term (so +12) and the other takes the opposite sign (-1).Write these as the second terms in the binomial expressions.(4n +12)*(4n - 1).Finally, divide out the 4 from the first bracket [this is to offset the earlier multiplication by 4] to give the answer:(n + 3)*(4n - 1)
What is the first 3 terms of 4n?
4, 8, 12
What are the first 3 terms of 4n plus3?
4n+3 For n = 1, the expression evaluates to 4+3 = 7 For n = 2, the expression evaluates to 8+3 = 11 For n = 3, the expression evaluates to 12+3 = 15
What is the first 3 terms for the nth term 4n-2?
Unless otherwise stated any series/sequence starts with n = 1 Then the first three terms are when n = 1, n= 2 and n = 3 and the series formula 4n - 2 gives the related results, 2, 6 and 10.
What are the first 3 terms for 4n plus 1?
As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------
What is 4n-1?
4n-1 = 3
What are the first four terms of 10x4n-1?
10*4n - 1 = 40n - 1 So t(1) =39 t(2) = 79 t(3) =119 t(4) = 159
What does n plus 4n-3 equals?
1
What is 4n plus 13 equals 1?
4n+13=1 -13 -134n=-12/4 /4n=-3
How would you factorise the equation 4n squared add 11n subtract 3?
4n2 + 11n - 3The following method is mathematically correct but may not be taught in school so be careful about using it.Multiply the last term by the coefficient of the first term:4n2 + 11n - 12Reduce the power of n in the first term by one and write them as the first terms in two binomial expressions:(4n )*(4n ).Find 2 factors of the last term (12), and since it is negative, the difference between these two factors should be the middle term (1 and 12). The larger of these takes the same sign as the middle term (so +12) and the other takes the opposite sign (-1).Write these as the second terms in the binomial expressions.(4n +12)*(4n - 1).Finally, divide out the 4 from the first bracket [this is to offset the earlier multiplication by 4] to give the answer:(n + 3)*(4n - 1)
What is the sum of first six terms of a sequence whose nth term is 4n-2?
The first 6 terms would be when n is 1, 2, 3, 4, 5, and 6. And since the nth term is 3 - 4n, you would simply substitute the first six numbers for n:* n = 1; 3 - 4(1); 3 - 4; -1 * n = 2; 3 - 4(2); 3 - 8; -5 * n = 3; 3 - 4(3); 3 - 12; -9 * n = 4; 3 - 4(4); 3 - 16; -13 * n = 5; 3 - 4(5); 3 - 20; -17 * n = 6; 3 - 4(6); 3 - 24; -21 -1, -5, -9, -13, -17, -21
What is 4n plus 3 equals 15?
4n + 3 = 15 4n +3 - 3 = 15 - 3 4n = 12 4n/4 = 12/4 n = 3
What is the answer to 4n 1-23-2n?
If you mean: 4n = 1-23-2n then 6n = -22 and so n = 11/3
