Q: What is the first 3 terms of 4n?

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3 7 11

20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.

They are -2, 2, 6, 10 and 14.

As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------

yes because the + and the - are two terms. hope this helps :3

Related questions

3 7 11

4n+3 For n = 1, the expression evaluates to 4+3 = 7 For n = 2, the expression evaluates to 8+3 = 11 For n = 3, the expression evaluates to 12+3 = 15

5

Unless otherwise stated any series/sequence starts with n = 1 Then the first three terms are when n = 1, n= 2 and n = 3 and the series formula 4n - 2 gives the related results, 2, 6 and 10.

20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.

5

4n + 3 = 15 4n +3 - 3 = 15 - 3 4n = 12 4n/4 = 12/4 n = 3

They are -2, 2, 6, 10 and 14.

As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------

yes because the + and the - are two terms. hope this helps :3

Starting from 1, your get: [4n + 5] = 9, 13, 17, 21, 25 Basically you find the first one and add 4 each time.

2