There are no first five because there is really no first: you can always use a smaller unit.
In terms of reasonably well known prefices, the answer could be:
yoctometre = 10-24 metres
zeptometre = 10-21 metres
attometre = 10-18 metres
femtometre = 10-15 metres
picometre = 10-12 metres.
But, the first could be defined as the Planck length = 1.616199*10-35 metres. This is the smallest measurable distance.
1 and 9
To find the points that are three units to the left of the Y-axis and five units from the origin, we start by noting that moving three units to the left of the Y-axis places us at the X-coordinate of -3. Since we want the distance from the origin to be five units, we can use the distance formula: ( \sqrt{(-3)^2 + y^2} = 5 ). Solving this gives ( y^2 = 16 ), resulting in ( y = 4 ) or ( y = -4 ). Thus, the two points are (-3, 4) and (-3, -4).
The run, combined with the rise (the distance in units up) creates the slope of a line. In the slope 5/3 , 5 is the rise and 3 is the run, meaning that to find the next point on the line you would first move up five units, then go to the right 3 units.
I assume it is five units and five tenths? Five units simply means five of something whole: for example, five whole pies. Five tenths means a pie is cut into ten slices, therefore five tenths is a half of a pie. So the answer must be five and a half units!
Go 19.75 units of distance in any direction. Turn 90 degrees clockwise and go 19.75 units of distance in a straight line. Turn 90 degrees clockwise and go 19.75 units of distance in a straight line. Turn 90 degrees clockwise and go 19.75 units of distance in a straight line.You will have travelled along a square route whose total distance is 79 units. Alternatively you could have turned counter clockwise each time.
Go 0.6325 units of distance in any direction. Turn 90 degrees clockwise and go 0.6325 units of distance in a straight line. Turn 90 degrees clockwise and go 0.6325 units of distance in a straight line. Turn 90 degrees clockwise and go 0.6325 units of distance in a straight line.You will have travelled along a square route whose total distance is 2.53 units. Alternatively you could have turned counter clockwise each time.
The horizontal distance between them is from -5 to 1, that is 6 units. The vertical distance between them is from 1 to 6, that is 5 units. So, using Pythagoras, the distance between then, along the diagonal, is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) units.
5,000,000 units.
There are two fives. The first is worth five units. The one after the decimal point is worth five tenths, or a half.
Production for five people was as follows: 8 units, 11 units, 6 units, 12 units, 8 units. What was their average production in units?
Just use the formula: distance = time x speed, or speed = distance / time. First convert everything to compatible units.Just use the formula: distance = time x speed, or speed = distance / time. First convert everything to compatible units.Just use the formula: distance = time x speed, or speed = distance / time. First convert everything to compatible units.Just use the formula: distance = time x speed, or speed = distance / time. First convert everything to compatible units.
The absolute value depends on it's "distance" from zero. So if it's to the right (positive) by 5 units, or to the left (negative) by five units, then it's absolute value is 5