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Let the height be (x+2) and the base be x:

1/2*height*base = area

1/2*(x+2)*x = 24

Multiply both sides by 2 and multiply out the brackets:

x2+2x = 48

x2+2x-48 = 0

Solving the above quadratic equation works out as:

x = -8 or x = 6 it must be the latter

Therefore: height = 8 inches and base = 6 inches

Use Pythagoras' theorem to find the hypotenuse:

82+62 = 100

hypotenuse = 10 inches

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Q: What are the height and hypotenuse of a right angle triangle whose height is 2 inches greater than its base and has an area of 24 square inches?
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