Let the height be (x+2) and the base be x:
1/2*height*base = area
1/2*(x+2)*x = 24
Multiply both sides by 2 and multiply out the brackets:
x2+2x = 48
x2+2x-48 = 0
Solving the above quadratic equation works out as:
x = -8 or x = 6 it must be the latter
Therefore: height = 8 inches and base = 6 inches
Use Pythagoras' theorem to find the hypotenuse:
82+62 = 100
hypotenuse = 10 inches
16.97056275 or about 17 inches
24.738633753705963298928459135844 sqrt(24*24 +6*6)
The hypotenuse of a right triangle with legs 12 inches and 16 inches is: 20 inches.
Providing that it is a right angle triangle its area is about 73 square inches. Solved by using Pythagoras and 1/2*base*height = area
The hypotenuse is 13.04 inches.
The hypotenuse of a right triangle with a base of 24 inches and height of 10 inches is: 26 inches.
16.97056275 or about 17 inches
Hypotenuse^2 = base^2 + height^2, substitute the given values Hypotenuse^2 = 5^2 + 12^2 Hypotenuse^2 = 25 + 144 Hypotenuse^2 = 169 Hypotenuse = √169 Hypotenuse = 13 Thus, the hypotenuse is 13 inches.
The median to the hypotenuse of a right triangle that is 12 inches in length is 6 inches.
24.738633753705963298928459135844 sqrt(24*24 +6*6)
The hypotenuse of a right triangle with legs 12 inches and 16 inches is: 20 inches.
Providing that it is a right angle triangle its area is about 73 square inches. Solved by using Pythagoras and 1/2*base*height = area
The hypotenuse of a triangle 18" x 18" is: 25.46 inches
The hypotenuse is 13.04 inches.
An equal sided triangle cannot have a hypotenuse!
The hypotenuse of a triangle is always the longest side. The hypotenuse of the right triangle measured 5 inches. In the formula "a2 + B2 = C2, the hypotenuse is always C.
The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 inches is: 10 inches.