0
9x2 + 4y = 36
∴ 4y = 36 - 9x2
∴ y = 9 - 9x2/4
also:
∴ 9x2 = 36 - 4y
∴ x2 = 4 - 4y/9
∴ x = (4 - 4y/9)1/2
This equation represents a parabolic curve, so we know it will intercept the y-axis at one point, and the x-axis at either zero or two points. Let's start with the x-axis:
y = 9 - 9x2/4
Let y = 0:
∴ 0 = 9 - 9x2/4
∴ 0 = 36 - 9x2
∴ 9x2 = 36
∴ x2 = 4
∴ x = +/- 2
So the curve intercepts the x axis at the points -2, 0 and 2, 0
As for the y axis:
x = (4 - 4y/9)1/2
Let x = 0:
∴ 0 = (4 - 4y/9)1/2
∴ 0 = 4 - 4y/9
∴ 0 = 45 - 4y
∴ 4y = 45
∴ y = 45/4 = 11 1/4
So the curve intercepts the y axis at the point 0, 11.25
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∙ 14y ago
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What are the x intercepts of the ellipse with the equation 9x squared plus 4y squared equals 36?
x = ±2
The polynomial below is a perfect square trinomial of the form A2 - 2AB plus B2 9x2-18x plus 36?
TrUE
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72
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What plus 9 equals 36?
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What equals 18?
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What are the x- and y-intercepts of the graph of 4x 3y equals 36?
I'll assume you mean the graph of 4x plus 3y = 36, since [4x*3y = 36] does not intersect either axis.If you only need to find the intercepts, and nothing else about the equation, then:the line intersects the x-axis when [y=0], so plug y=0 and solve for x:4*x + 3*0 = 36 --> 4*x = 36 --> x = 9, so it intercepts the x-axis at (9,0)for y-intercept, plug [x=0]: 4*0 + 3*y = 36 --> 3*y = 36 --> y = 12: at point (0,12)
