I'll assume you mean the graph of 4x plus 3y = 36, since [4x*3y = 36] does not intersect either axis.
If you only need to find the intercepts, and nothing else about the equation, then:
the line intersects the x-axis when [y=0], so plug y=0 and solve for x:
4*x + 3*0 = 36 --> 4*x = 36 --> x = 9, so it intercepts the x-axis at (9,0)
for y-intercept, plug [x=0]: 4*0 + 3*y = 36 --> 3*y = 36 --> y = 12: at point (0,12)
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2x + 3y = 6 can be written in the standard slope-intercept form of y= mx + c, where 'm' is the slope. 3y = -2x + 6 y = -⅔x + 2 The slope of this linear graph is -⅔.
If 3y = 12, 2y = 8
5x -6y=-30 5x-6y=30 (2x+3y) (2x-3y)=30 4x+6y=30 4x=30 x=30/4
2x + 3y = 29x= 4 find x 29x= 4 x = (4/29) sub x into the first part of the sum 2x + 3y = 4 2*(4/29) + 3y = 4 note * means multiply (8/29) + 3y = 4 3y = 4 - (8/29) 3y = (108/29) note 4* 29 minus 8 = 108 y = (36/29) there is probably a quicker way to do this.
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