Best Answer

9x2 + 27x - 36

= 9(x2 + 3x - 4)

= 9(x + 4)(x - 1)

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Q: How do you factor 9x squared plus 27x minus 36?

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(5x - 2)(x - 5)

9xy(3xy - 4)

I also need to know the answer to this problem. Can anyone answer it?

You try to find two factors of -58 whose sum is -27 .You find that -29 and +2 will do it, so . . .x2 - 27x - 58 = (x - 29) (x + 2)

Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)

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the answer is (3x-2)(9x squared+6x+4)

3x2 + 27x +60

9xy(3xy - 4)

(8x + 9)(3x^2 - 1)

I also need to know the answer to this problem. Can anyone answer it?

You try to find two factors of -58 whose sum is -27 .You find that -29 and +2 will do it, so . . .x2 - 27x - 58 = (x - 29) (x + 2)

20x2 - 27x -8 20 * -8 is -160, and -32 and 5 add to -27 20x2 - 32x + 5x - 8 4x(5x-8) + 1(5x-8) (4x + 1)(5x-8)

Divide the entire equation by 9. (9x2 + 27x + 18)/9 would then be 9(x2 + 3x +2) The factors of this equation would be 9(x + 1)(x + 2)

16x2 + 27x - 28 doesn't factor. Applying the quadratic formula, we find two real solutions:(-27 plus or minus the square root of 2521) divided by 32x = 0.725298776329149x = -2.412798776329149

5x2 - 27x - 18 = (5x + 3)(x - 6)

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