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Let one base be x+12 and the other base be x:

1/2*(sum of bases)*height = area

1/2*(x+12+x)*6 = 180 sq cm

Multiply both sides by 2:

(x+12+x)*6 = 360

Multiply out the brackets:

6x+72+6x = 360

6x+6x = 360-72

12x = 288

Divide both sides by 12 to find the value of x:

x = 24

Therefore: the bases are 36 cm and 24 cm respectively

Check: 1/2*(36+24)*6 = 180 sq cm

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Q: What are the lengths of the bases of an isosceles trapezoid when one base is 12 cm more than the other its area is 180 sq cm and its height is 6 cm?
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