Let one base be x+12 and the other base be x:
1/2*(sum of bases)*height = area
1/2*(x+12+x)*6 = 180 sq cm
Multiply both sides by 2:
(x+12+x)*6 = 360
Multiply out the brackets:
6x+72+6x = 360
6x+6x = 360-72
12x = 288
Divide both sides by 12 to find the value of x:
x = 24
Therefore: the bases are 36 cm and 24 cm respectively
Check: 1/2*(36+24)*6 = 180 sq cm
Yes but the parallel bases are of different lengths
23.5
Two bases that are parallel to each other and two sides that are of unequal lengths unless it is an isosceles trapezoid whereas the sides will be equal in length.
parallel
Divide area by one half of the sum of the bases. You need to know base lengths to get height
28.5
28.5
23.5 Units
25.5 units
Yes but the parallel bases are of different lengths
With the information given it can be any height greater than zero units. If the area was given, or the lengths of the equal sides were given, then the height can be calculated specifically.
If the lengths of the bases are also given then rearrange the area of the trapezoid formula so that the height is the subject.
23.5
False.
False.
Height of trapezoid = 2*area/sum of parallel sides
Two bases that are parallel to each other and two sides that are of unequal lengths unless it is an isosceles trapezoid whereas the sides will be equal in length.