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If the bases of an isosceles trapezoid have measures of 8 inches and 12 inches what is the measure of its median?
The average(mean) of the two bases. (8+12)/2=10
What is the perimeter of ann isosceles trapezoid with a height of 4 inches and bases of 10 and 12?
Use Pythagoras to find the lengths of the sides: 42+12 = 17 and the square root of this is the length of the sides which works out at about 4.123105626 Perimeter: 2*4.123105626+10+12 = 30.24621125 inches
What is the area of a trapezoid if its bases are 12 and 18 meters long and its height is 4 meters?
the formula for the area of a trapezoid is one half the sum of its bases times the height. So, A = .5(b1+b2)h = .5(18+12)4 = 60 meters2
An isosceles trapezoid has base angles of 45 degrees and bases of lengths 9 and 15 The area of the trapezoid is?
You can deduce that its height is 3, since the perpendiculars dropped from the shorter base create a central rectangle and two identical, right, isosceles triangle with base and height 3.3(9+15)/2=36We know the piece of the base is 3 because we subtract 9 (top base) from 15 (bottom base) and that gives us 6, then divide that in half because there are 2 triangles, so we get 3this only works for isosceles trapezoidsThen because the triangles on the sides are isosceles, the length of their bases is the same so if the horizontal base is 3, then the vertical base is also 3, which is the height of the trapezoidArea = average of bases times heightArea = (base 1 + base 2)/2 x heightArea = (15 + 9)/2 x 3Area = 24/2 x 3Area = 12 x 3 = 36
Isosceles trapezoid abcd has an area of 276 in squared if ad equals 13 inches and de equals 12 inches find ab?
Isosceles trapezoid ABCD has an area of 276 If AD = 13 inches and DE = 12 inches, find AB.
If the bases of an isosceles trapezoid have measures of 8 inches and 12 inches what is the measure of its median?
The average(mean) of the two bases. (8+12)/2=10
What is the perimeter of ann isosceles trapezoid with a height of 4 inches and bases of 10 and 12?
Use Pythagoras to find the lengths of the sides: 42+12 = 17 and the square root of this is the length of the sides which works out at about 4.123105626 Perimeter: 2*4.123105626+10+12 = 30.24621125 inches
What is the area of a trapezoid if its bases are 12 and 18 meters long and its height is 4 meters?
the formula for the area of a trapezoid is one half the sum of its bases times the height. So, A = .5(b1+b2)h = .5(18+12)4 = 60 meters2
What is the height of a trapezoid with bases 7in and 12 in?
We cannot determine the height of a trapezoid with just the lengths of the bases. Additional information such as the length of the parallel sides or any angles would be needed to calculate the height accurately.
The demension of a right trapezoid-shaped figure has bases of 28 inches and 16 inches and the slant height is 17 inches What is the lenght in inches of the height?
If you draw another altitude parallel to the height (the side which is perpendicular to the bases) of the trapezoid, you can see that a right triangle is formed.In this triangle the hypotenuse length is 17 in, and the base length equals to 28 - 16 = 12 in. From the Pythagorean theorem, height length = √(17 - 12) ≈ 12 in.Or find the measure of the angle (call it A) opposite to the height such as:cos A = 12/17A = cos-1 (12/17) ≈ 45⁰, which tells us that this right triangle is an isosceles triangle.Therefore, the height is (congruent with base) 12 inches long
What is the area of a trapezoid with bases of 12 and 14 and height of 8?
Area = 1/2*(14+12)*8 = 104 square cm
What is the area of a trapezoid bases are 12Cm and 8Cm and the height is 5Cm?
1/2*(12+8)*5 = 50 square cm
If the area of the trapezoid is 150 square units and the bases are 8 and 17 what is the value of x its height?
x (height) = 12 units. area_trapezoid = ½ × sum_of_bases × height → height = 2 × area_trapezoid ÷ sum_of_bases → height = 2 × 150 ÷ (8 + 17) = 12 units
What is the area of a trapezoid with the height of 12cm and the base of 15 cm?
The formula to calculate the area of a trapezoid is (1/2) * sum of the bases * height. Given that the height is 12 cm and the bases are 15 cm and another side, the area can be calculated as (1/2) * (15 + b) * 12, where b is the length of the other base.
An isosceles trapezoid has base angles of 45 degrees and bases of lengths 9 and 15 The area of the trapezoid is?
You can deduce that its height is 3, since the perpendiculars dropped from the shorter base create a central rectangle and two identical, right, isosceles triangle with base and height 3.3(9+15)/2=36We know the piece of the base is 3 because we subtract 9 (top base) from 15 (bottom base) and that gives us 6, then divide that in half because there are 2 triangles, so we get 3this only works for isosceles trapezoidsThen because the triangles on the sides are isosceles, the length of their bases is the same so if the horizontal base is 3, then the vertical base is also 3, which is the height of the trapezoidArea = average of bases times heightArea = (base 1 + base 2)/2 x heightArea = (15 + 9)/2 x 3Area = 24/2 x 3Area = 12 x 3 = 36
What is the area of a trapezoid with a length of 7 height of 3 and a width of 12?
Area of a trapezoid = 0.5*( sum of parallel sides)*height
What is the area of a trapezoid if the bases are 15 feet LONG and 7 feet long and the height is 12 feet?
Area = 0.5*(15+7)*12 = 132 square feet
