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Tangent lines stem from the point: (8,2)

Equation of circle: x^2 +y^2 -4x -8y -5 = 0

Completing the squares: (x-2)^2 +(y-4)^2 -4 -16 -5 = 0

So: (x-2)^2 +(y-4)^2 = 25 which is the radius squared

Centre of circle: (2, 4)

Distance from (2, 4) to (8, 2) = 40 which is the distance squared

Lengths of tangents using Pythagoras: 40-25 = 15 => square root of 15

Note that the distance from (2, 4) to (8, 2) is actually the hypotenuse of a right angle triangle.

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Q: What are the lengths of the tangent lines from the point 8 2 when they touch the circle x2 plus y2 -4x -8y -5 equals 0 on the Cartesian plane showing work?
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