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What is the equation of a circle whose diameter endpoints are at 2 -3 and 8 7 on the Cartesian plane and what are the tangent equations touching its endpoints showing work?
Wiki User
∙ 7y ago
Endpoints: (2, -3) and (8, 7)
Centre of circle: (5, 2)
Radius of circle is the square root of 34
Equation of the circle: (x-5)^2 +(y-2)^2 = 34
Slope of radius: 5/3
Slope of tangents: -3/5
1st tangent equation: y--3 = -3/5(-2) => 5y = -3x-9
2nd tangent equation: y-7 = -3/5(x-8) => 5y = -3x+59
Wiki User
∙ 7y ago
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What is the perpendicular bisector equation of the line segment whose endpoints are at -4 -10 and 8 -1 on the Cartesian plane?
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What is the equation of a circle whose diameter endpoints are at 10 -4 and 2 2 on the Cartesian plane and what are the perpendicular equations to its endpoints showing work?
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