3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36.
There are an infinite number of multiples for 3
34, 68, 102, 136, 170.
The first 15 multiples of 136: 136, 272, 408, 544, 680, 816, 952, 1088, 1224, 1360, 1496, 1632, 1768, 1904, 2040 . . . ∞
Any number has an infinite number of multiples.
Multiples of 34 include 34, 68, 102, 136 and so on. For them to be common, they need to be compared to another set of multiples. Common multiples of 3 and 4 include any multiple of 12.
Factors of the number will also be factors of the number's multiples. Multiples of the number will also be multiples of the number's factors.
No multiples of 2 are factors of 3.
X/5= 136; X= 136x5 = 668; 668+3=671
Multiples of 6 must also be multiples of 1, 2 and 3.
They are all multiples of 3.
Multiples of 3
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72