NO. When a number is odd, not all of its multiples are odd.Example: 3 is an odd number.Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24,...Multiples of 3 which are not odd: 6, 12, 18, 24, ...
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, . . .
Take the multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, etc. Now, eliminate every fourth number in the sequence (the multiples of 4). The remaining numbers will be multiples of 3, but not of 4.
3, 6, 9, 12, 15, 18
The number is infinite, beginning with these: 72, 144, 216, 288, 360, 432 . . . ∞
It is: 360
NO. When a number is odd, not all of its multiples are odd.Example: 3 is an odd number.Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24,...Multiples of 3 which are not odd: 6, 12, 18, 24, ...
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, . . .
Take the multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, etc. Now, eliminate every fourth number in the sequence (the multiples of 4). The remaining numbers will be multiples of 3, but not of 4.
It depends on the number. The multiples of 4 that are under 26 are 4, 8, 12, 16, 20, 24. The multiples of 3 under 26 are 3, 6, 9, 12, 15, 18, 21, 24. The multiples of 10 under 24 are 10, 20.
3, 6, 9, 12, 15, 18, 21, 24, 27 (multiply any number by three or just keep on adding three to the number 3. these are all multiples) hope i helped
There are an infinite number of multiples of any number. Therefore, it is impossible to list all the multiples of 3 and 4. A list of the first 10 multiples: Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30 Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36.
If: 3x+9 = 24 Then: 3x = 24-9 So: 3x = 15 => x = 15/3 The number is 5
12,24,36,48,60,72,84.....The multiples of 12 are12:12,24,36,48,60,72,84,96,108,120,132,and 144
24 this is how it breaks down -15 + x = 9 => x= 9 + 15 => x= 24
The first three multiples of 12 are 12, 24, and 36.