25, 30, 35, 40, 45, 50, 55
{59x | x ∈ I}
59-21 = 38
20, 25, 30, 35, 40, 45, 50, 55.
59, 118, 177, 236, 295.
It consists of the multiples of 59, from 1 to 10 (or 12).
To find the number of whole numbers between 1 and 500 that are divisible by 6 but not by 8, we need to find the numbers that are multiples of 6 and not multiples of 8. First, we find the multiples of 6 by dividing 500 by 6, which gives us 83 whole multiples. Next, we find the multiples of 8 by dividing 500 by 8, which gives us 62 whole multiples. To find the numbers that are multiples of 6 but not of 8, we subtract the common multiples of 6 and 8, which is 24, from the total multiples of 6, resulting in 83 - 24 = 59 whole numbers between 1 and 500 that are divisible by 6 but not by 8.
Any of its multiples
59
59, 118, 177, 236, 295, 354, 413, 472, 531, 590 .....and so on, because multiples never stop.
The GCF of 21 and 59 is 1.
17*59 = 1003
38 + a number = 59 so the unknown number = 59 - 38 = 21