Since 9 is not a prime, all [positive integral] multiples of 9 are exactly divisible.
Any of their multiples
As 9 is a multiple of 3, any multiple of 9 will do : 9,18,27,36,45,....
It can be, so please rephrase your question. All multiples of 40 are also dividible by 8.
The infinitely many multiples of 34248, all of which belong to the set of numbers of the form 34248*k where k is an integer.
9 multiples
The multiples of 6 is 6,12,18,24,30,36,42,48,54,60,66,72,78,84,90.................. The multiples of 9 is 9,18,27,36,45,54,63,72,81,90,99,108,117,126,135...............
The numbers that are divisible by 2, 3, 5, and 9 are known as common multiples of these four numbers. The first common multiple that is greater than 5 is 90. Therefore, 90 is an example of a number that is divisible by 2, 3, 5, and 9.
The first three multiples of 3 are 3, 6, 9 The first three multiples of 9 are 9, 18, 27 As the lowest common multiples of 3 and 9 is 9, the common multiples of 3 and 9 are the multiples of 9, thus: The first three common multiples of 3 and 9 are 9, 18, 27
The multiples of 9 are: 1 and 9 3 and 3
Common multiples of 9 and 10 are all of the multiples of 90.
yes
Nope, neither are multiples of 9.