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Using the rule:

U(n) = (11*n^5 - 150*n^4 + 785*n^3 - 1950*n^2 + 2384*n - 960)/120 for n = 1, 2, 3, ...

the next three are 118, 344, 835.

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Q: What are the next three numbers in the pattern 1 2 3 4 8 32?
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Related questions

What are the next three numbers in the following sequence 1 2 4 8?

It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.


What is the next three numbers 33 32 30 27?

Well, judging by the sequence of numbers, the pattern would be to subtract one more than the last time from each new number. Meaning 33-1=32 then 32-2=30 then 30-3=27. The next three numbers would be 27-4=23 and 23-5=18 and finally 18-6=12. So 23 18 and 12 would be the next three numbers in sequence.


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Each number is half the previous number. The series formula is a(n) = 32 *(½)n⁻¹ 32, 16, 8, 4, 2, 1, 0.5 The next three numbers in the sequence are : 0.25, 0.125, 0.0625


What is the sum of 28 and the next two consecutive composite numbers?

The three composite numbers are 28, 30 and 32. Their sum is 90.


What is the pattern for 4111825?

If you mean 4 11 18 25 then the next number is 32 because the numbers are increasing by increments of 7


What comes next 02 34 66 98?

The common difference between the numbers is 32. Therefore, the next two numbers after 98 will be 98 + 32 = 130 and 130 + 32 = 162.


Which rule describes this pattern 25 32 28 35 31 38?

The pattern is... add 7 then subtract 4. The next two numbers would be 45 & 41.


What are the next 2 numbers in the pattern -1 2 -4 8 -16?

32, -64 (you are doubling and reversing sign, i.e. multiplying by -2)


What are three consecutive numbers that add up to 32?

There is no such set of numbers.


What is the next number in the number pattern 1 5 10 14 28?

The pattern is +4, 2x, +4, 2x, and so on. The next number is 32.


What are the next four composite numbers after 30?

The next four composite numbers after 30 are 32, 33, 34 and 35.


What is the pattern of the infinite sequence 2 3 7 16?

The next numbers in the series are 32 and 57. This is reached by adding successive square numbers 1, 4, 9, 16, 25 and so on.