Using the rule:
U(n) = (11*n^5 - 150*n^4 + 785*n^3 - 1950*n^2 + 2384*n - 960)/120 for n = 1, 2, 3, ...
the next three are 118, 344, 835.
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
Each number is half the previous number. The series formula is a(n) = 32 *(½)n⁻¹ 32, 16, 8, 4, 2, 1, 0.5 The next three numbers in the sequence are : 0.25, 0.125, 0.0625
The pattern is... add 7 then subtract 4. The next two numbers would be 45 & 41.
There is no such set of numbers.
The next four composite numbers after 30 are 32, 33, 34 and 35.
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
Well, judging by the sequence of numbers, the pattern would be to subtract one more than the last time from each new number. Meaning 33-1=32 then 32-2=30 then 30-3=27. The next three numbers would be 27-4=23 and 23-5=18 and finally 18-6=12. So 23 18 and 12 would be the next three numbers in sequence.
Each number is half the previous number. The series formula is a(n) = 32 *(½)n⁻¹ 32, 16, 8, 4, 2, 1, 0.5 The next three numbers in the sequence are : 0.25, 0.125, 0.0625
The three composite numbers are 28, 30 and 32. Their sum is 90.
If you mean 4 11 18 25 then the next number is 32 because the numbers are increasing by increments of 7
The common difference between the numbers is 32. Therefore, the next two numbers after 98 will be 98 + 32 = 130 and 130 + 32 = 162.
The pattern is... add 7 then subtract 4. The next two numbers would be 45 & 41.
There is no such set of numbers.
The next four composite numbers after 30 are 32, 33, 34 and 35.
32, -64 (you are doubling and reversing sign, i.e. multiplying by -2)
The next numbers in the series are 32 and 57. This is reached by adding successive square numbers 1, 4, 9, 16, 25 and so on.
The numbers are 30, 31 and 32.