The next number in the series is 57. This is reached by adding successive square numbers 1, 4, 9, 16, 25 and so on.
The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.
Partial sums for a sequence are sums of the first one, first two, first three, etc numbers of the sequence. So, the series of partial sums is:2, 6, 14, 30, 62, ...It is the sequence whose nth term isT(n) = 2^(n+1) - 2 for n = 1, 2, 3, ...
The wrong number in this sequence is 20. The pattern in the sequence is doubling each number, so it should go 2, 4, 8, 16, 32, 64, etc. However, 20 breaks this pattern by not being double the previous number.
42, each number in the sequence is the addition of the previous two: 2-2-4-6-10-16-26 2+2=4 4+6=10 6+10=16 10+16=26 16+26=42
The next number in the series is 57. This is reached by adding successive square numbers 1, 4, 9, 16, 25 and so on.
The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.
The next number in the sequence 2, 4, 16, 64 is 256.
Partial sums for a sequence are sums of the first one, first two, first three, etc numbers of the sequence. So, the series of partial sums is:2, 6, 14, 30, 62, ...It is the sequence whose nth term isT(n) = 2^(n+1) - 2 for n = 1, 2, 3, ...
Final sequence:- 1,4,9,16,25,36,49,64,81,100,121,144,169,196… This is a pattern of square numbers. 1^2=1, 2^2=2, 3^2=9, 4^2=16, and 5^2=25. The next number would be 36 because 6^2 equals 36.
This is a sequence based on the squares of numbers (positive integers) but starting with the square of 2. Under normal circumstances the sequence formula would be n2 but as the first term is 4, the sequence formula becomes, (n + 1)2. Check : the third term is (3 + 1)2 = 42 = 16
42, each number in the sequence is the addition of the previous two: 2-2-4-6-10-16-26 2+2=4 4+6=10 6+10=16 10+16=26 16+26=42
From the given sequence, the pattern appears to be 47-42=4, 42/3=14, 14*2=28, 28-4=24, 24/3=8, 8*2=16 and therefore the next number will be 16-4=12.
A geometric sequence is : a•r^n while a quadratic sequence is a• n^2 + b•n + c So the answer is no, unless we are talking about an infinite sequence of zeros which strictly speaking is both a geometric and a quadratic sequence.
This sequence is called the doubling sequence.
There are an infinite number of numbers that have a difference of 16, 16 and 0 is a pair that fits this.
The Fibonacci sequence is infinite. The next two terms are 89 and 144.