Set up as follows:
x+(2x+1)=3(2x+1)-20
Do the algebra:
3x+1=6x+3-20
3x+1=6x-17
3x+18=6x
18=3x
x=6 (represents the smallest number)
larger # is 2x+1....substitute 6 for x
2(6)+1=13
two numbers are 6 and 13
12 and 28
The numbers are: 3 and 12
x + y = 14 3x + 2y = 33 x = 5 y = 9
The smaller number is 9 . You should certainly be able to handle it from there.
There is no solution. 1.4 times the smaller is less than 1.5 times the smaller which, in turn, is less than 1.5 times the larger. 1.4 times the smaller is, therefore, smaller than 1.5 times the larger and certainly not 3 more than 1.5 times the larger.
a=3b
The larger number is 12.
12 and 28
13 and 6
The numbers are: 7 and 13
The numbers are: 3 and 12
The larger of two numbers is 8 more than 4 times the smaller if the larger number is increased by four times the smaller the result is 40. From this statement, we can calculate the values of the numbers where you get the value of the larger number to be 24 and that of the smaller number to be 4.
101 and 26
x + y = 14 3x + 2y = 33 x = 5 y = 9
Generally yes, but not in all cases. The largest prime number has over 22 million digits but only two factors whereas 60 has six times as many factors.
The smaller number is 9 . You should certainly be able to handle it from there.
First of all you need serious help with your grammar, more than your math. I will try to make sense of what you wrote. 24 and 4 are the numbers you are looking for.