109 is a Prime number. Therefore, the only divisors are 1and 109.
To find how many two-digit numbers ( n ) result in a remainder of 4 when dividing 109, we can express this mathematically as ( 109 \equiv 4 \mod n ). This simplifies to ( 109 - 4 = 105 ) being divisible by ( n ), or ( n ) being a divisor of 105. The divisors of 105 that are two-digit numbers are 15, 21, 35, and 105, giving us a total of 4 two-digit divisors.
The single-digit divisors of 7,000 are 1, 2, 4, 5, 7, 8.
The single digit divisors of 420 are: 1,2,3,4,5,6, and 7
0.029
The single-digit divisors of 27,000 are: 1, 2, 3, 4, 5, 6, 8, 9.
12458
The single-digit divisors of 3,456 are: 1, 2, 3, 4, 6, 8 and 9.
I think you mean, the largest four digit number that has exactly three divisors. 2X3X1663=9,978
Find the quotient
1, 2, 3, 4, 5, 6, 7
2
23 divide 3974